Pure
OLL parity
Make the top cross as on a 3x3, then: Count the last-layer dedges showing no top colour on top: one or three means OLL parity; none, two or four means no parity: an ordinary 3x3 OLL.
Your status
Algorithms (4)
2R' U2 2L F2 2L' F2 2R2 U2 2R U2 2R' U2 F2 2R2 F2
My choice
22 HTM · 15 STM · 34 QTM
rotationless
<U,R,F,L>
SpeedCubeDB, 30 votes
y2 F R U R' U' F' U Rw U2 x Rw U2 Rw U2 Rw' U2 Lw U2 Rw' U2 Rw U2 Rw' U2 Rw'
24 HTM · 24 STM · 32 QTM
rotation
<U,R,F,L>
SpeedCubeDB, 14 votes
R' U2 Rw' U2 Rw U2 Rw2 U2 x' U2 Rw' U2 Rw U2 l' U2 Rw U2 Rw R
19 HTM · 19 STM · 29 QTM
3-gen
rotation
<U,R,L>
SpeedCubeDB, 3 votes
R U2 R' U' Rw U2 x Rw U2 Rw U2 Rw' U2 Lw U2 Rw' U2 Rw U2 Rw' U2 Rw' F R' F' R
25 HTM · 25 STM · 34 QTM
rotation
<U,R,F,L>
SpeedCubeDB, 3 votes
How this case is verified
The case is the source's setup, checked against the source's case image. Setup: F2 2R2 F2 U2 2R U2 2R' U2 2R2 F2 2L F2 2L' U2 2R. Every algorithm above was run by our logic engine from that state and reaches "oll-solved", keeping first-layers.