Basic

OLL parity
Make the top cross as on a 3x3, then: Count the last-layer dedges showing no top colour on top: one or three means OLL parity; none, two or four means no parity: an ordinary 3x3 OLL.
Your status
Drill this case

Algorithms (4)

Rw U2 x Rw U2 Rw U2 Rw' U2 Lw U2 Rw' U2 Rw U2 Rw' U2 Rw'
My choice
17 HTM · 17 STM · 25 QTM
3-gen
rotation
<U,R,L>
SpeedCubeDB, 38 votes
Rw' U2' Rw U2 Rw U2' Rw2' F2 Rw' U2 Rw' U2' F2 Rw2 F2
15 HTM · 15 STM · 25 QTM
3-gen
rotationless
<U,R,F>
SpeedCubeDB, 29 votes
Rw2 B2 U2 Lw U2 Rw' U2 Rw U2 F2 Rw F2 Lw' B2 Rw2
15 HTM · 15 STM · 25 QTM
rotationless
<U,R,F,L,B>
SpeedCubeDB, 10 votes
Rw2 B2 Rw' U2 Rw' U2 x' U2 Rw' U2 Rw U2 Rw' U2 Rw2 U2 x
15 HTM · 15 STM · 25 QTM
3-gen
rotation
<U,R,B>
SpeedCubeDB, 7 votes

How this case is verified

The case is the source's setup, checked against the source's case image. Setup: Rw U2 Rw U2 Rw' U2 Rw U2 Lw' U2 Rw U2 Rw' U2 Rw' x' U2 Rw'. Every algorithm above was run by our logic engine from that state and reaches "oll-solved", keeping first-layers.