M
OLL parity
Make the top cross as on a 3x3, then: Count the last-layer dedges showing no top colour on top: one or three means OLL parity; none, two or four means no parity: an ordinary 3x3 OLL.
Your status
Algorithms (4)
M Rw U2 x Rw U2 Rw U2 Rw' U2 Lw U2 Rw' U2 Rw U2 Rw' U2 Rw' M'
My choice
21 HTM · 19 STM · 29 QTM
rotation
<U,R,L,M>
SpeedCubeDB, 8 votes
y2 2R2 U2 2R2 Uw2 2R2 Uw2 Rw U2 x Rw U2 Rw U2 Rw' U2 Lw U2 Rw' U2 Rw U2 Rw' U2 Rw'
26 HTM · 23 STM · 43 QTM
3-gen
rotation
<U,R,L>
SpeedCubeDB, 3 votes
M Rw2 B2 U2 Lw U2 Rw' U2 Rw U2 F2 Rw F2 Lw' B2 Rw2 M'
19 HTM · 17 STM · 29 QTM
rotationless
<U,R,F,L,B,M>
SpeedCubeDB, 2 votes
M Rw' U2' Rw U2 Rw U2' Rw2' F2 Rw' U2 Rw' U2' F2 Rw2 F2 M'
19 HTM · 17 STM · 29 QTM
rotationless
<U,R,F,M>
SpeedCubeDB, 1 votes
How this case is verified
The case is the source's setup, checked against the source's case image. Setup: M Rw U2 Rw U2 Rw' U2 Rw U2 Lw' U2 Rw U2 Rw' U2 Rw' x' U2 Rw' M'. Every algorithm above was run by our logic engine from that state and reaches "oll-solved", keeping first-layers.